Basic Photography Course

This computation can be done with lenses marked in
millimeters; however, the result will also be in
millimeters. At this point, you must convert millimeters

to inches as follows:

A = FG

12 inches x 12 feet

A =

9 inches

I = 305mm x 10 ft

= 101mm x .04 (conversion factor) = 4 inches

Where:

I = the image size

F = the focal length

G = the object size

A = the distance from the lens to the object

PROBLEM 2: A 24-inch focal-length lens is used to
photograph an object 10 feet high from a distance of 30
feet. What is the length of the image? The formula and
computations are as follows:

F =IA

F = 4 x 20

I = 8 inches

or, solving to prove the unit of measure of the result.

I = F G

I =24 x 10

3 0

I = 24 inches x 10 feet

30 feet

I = 8 inches or image size

I = 8 inches

As an example of a typical situation whereby you

can make use of the IA = FG formula, suppose you are
requested to make a 9-inch photograph of a board 12

feet long. This board is mounted on a wall and the
maximum distance from that wall to the opposite side

of the room is 20 feet. Is it possible to make this
photograph using an 8x10 camera equipped with a

12-inch focal-length lens?

G = IA

G = 9 inches x 16 feet

12 inches

The known values are object size (12-foot board),

requested image size (9 inches), and the focal length (12
inches). The unknown factor is the necessary
lens-to-subject distance required to make the
photograph using this camera. The formula and
computations are as follows:

IA = FG

A= 16 feet

The required lens-to-subject distance equals 16 feet.

The answer to this problem then would be yes, since the
required lens-to-subject distance is only 16 feet. This
allows the photographer 4 feet (20 - 16 = 4) in which to
set up and operate the camera.

PROBLEM 3: An image 4 inches long of an object 8
feet high at a distance of 20 feet is focused on the film
plane. What is the lens focal length?

IA = FG

F = 10, or focal length equals 10 inches

Another problem to illustrate the application of the

proportion I:F=G:A follows: When using an 8x10
camera equipped with a 12-inch focal-length lens to
obtain a 9-inch image from a distance of 16 feet, you
can photograph an object of what maximum length? To
solve this problem, you should have the formula and
computation as follows:

G = 12 feet

The maximum length of an object that can be

photographed with this 12-inch lens, using an image size
of 9 inches from a distance of 16 feet, is 12 feet.

Using Various Lenses

It is possible for you to take all your pictures with

only one lens. But before long, you will want to expand
your range of lenses to become a more versatile
photographer.

Within our Navy, 35mm single-lens reflex (SLR)

cameras are coming into ever-increasing use. Every

Navy photo unit should have several SLR cameras, and

l-30

contents

Basic Photography Course

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DOFMaster for Windows On-line Depth of Field Calculator DOFMaster for Mobile Devices On-line Depth of Field Table Hyperfocal Distance Chart Articles FAQ Recommended Books Support Contact Links Home As an Amazon Associate I earn from qualifying purchases.	contents <- previous page next page -> This computation can be done with lenses marked in millimeters; however, the result will also be in millimeters. At this point, you must convert millimeters to inches as follows: A = FG I 12 inches x 12 feet A = 9 inches I = 305mm x 10 ft 30 = 101mm x .04 (conversion factor) = 4 inches Where: I = the image size F = the focal length G = the object size A = the distance from the lens to the object PROBLEM 2: A 24-inch focal-length lens is used to photograph an object 10 feet high from a distance of 30 feet. What is the length of the image? The formula and computations are as follows: F =IA G F = 4 x 20 8 I = 8 inches or, solving to prove the unit of measure of the result. I = F G A I =24 x 10 3 0 I = 24 inches x 10 feet 30 feet I = 8 inches or image size I = 8 inches As an example of a typical situation whereby you can make use of the IA = FG formula, suppose you are requested to make a 9-inch photograph of a board 12 feet long. This board is mounted on a wall and the maximum distance from that wall to the opposite side of the room is 20 feet. Is it possible to make this photograph using an 8x10 camera equipped with a 12-inch focal-length lens? G = IA F G = 9 inches x 16 feet 12 inches The known values are object size (12-foot board), requested image size (9 inches), and the focal length (12 inches). The unknown factor is the necessary lens-to-subject distance required to make the photograph using this camera. The formula and computations are as follows: IA = FG A= 16 feet The required lens-to-subject distance equals 16 feet. The answer to this problem then would be yes, since the required lens-to-subject distance is only 16 feet. This allows the photographer 4 feet (20 - 16 = 4) in which to set up and operate the camera. PROBLEM 3: An image 4 inches long of an object 8 feet high at a distance of 20 feet is focused on the film plane. What is the lens focal length? IA = FG F = 10, or focal length equals 10 inches Another problem to illustrate the application of the proportion I:F=G:A follows: When using an 8x10 camera equipped with a 12-inch focal-length lens to obtain a 9-inch image from a distance of 16 feet, you can photograph an object of what maximum length? To solve this problem, you should have the formula and computation as follows: G = 12 feet The maximum length of an object that can be photographed with this 12-inch lens, using an image size of 9 inches from a distance of 16 feet, is 12 feet. Using Various Lenses It is possible for you to take all your pictures with only one lens. But before long, you will want to expand your range of lenses to become a more versatile photographer. Within our Navy, 35mm single-lens reflex (SLR) cameras are coming into ever-increasing use. Every Navy photo unit should have several SLR cameras, and l-30 contents Basic Photography Course <- previous page next page ->	As an Amazon Associate I earn from qualifying purchases.
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